De-formation™ Force & Work

Image 1

The simplest methodology is sought to represent material deformation. In the image above, an example of a beam under gravitational influence from a central fulcrum is indicated, in the upper portion. The latter time sequence of the same beam is displayed with more de-formation than earlier, from equal mass apportioned to each end for all timeframes.

In the earlier example gravity deforms the beam under its own mass. The deformation from the mass, placed under gravitational acceleration, at the ends of the beam can substitute mechanical, compressional deformation. The one measurement achieves both objectives accurately and precisely.

The distortion of the beam is arithmetically cumulative of the self de-formation added to the extra deformation from the added end-point masses. Where the dimensional constant, h[2], will be generally substituted by h - a complete dimension. The deformation rate can be determined by the deformation work done.

The equation for that relationship is W = m * g * ( hf [1] + hf [2] ), where hf = fall height, or the height of the beam’s end on its fall from the perfect horizontal position.

The most important aspect to consider is W ∝ h , where W is the deformation dimension. To determine deformation force, simply divide work (W) by distance (d). (Work is power-time displacement.) The power of a contact object is also easily measured as W/T [ contact] . That example is where

T = n * T [c], and

n = scalar or harmonic

T [c] = Critical or unitary period, 1 s

This method is a lot simpler, in conceptual interpretation and familiarity than σ = 2 * M * G / I .

W = m * g * h

m = 7 kg

g ~ 9.81 m / s^2

h [1] = 1 m , for t [1]

h [3] = h [1] + h [2]

h [3] = 3m , for t [2]

Eg. 1

h = 1 m

W = 7 kg * 9.81 m / s^2 * 1 m

W = 6.867 * 10 J ,

F = 6.867 * 10 J / 1 m , 6.867 * 10 N

Eg. 2

h = 1 m + 2 m , 3 m

W = 7 kg * 9.81 m / s^2 * ( 1 m + 2 m ) ,

W = 206.01 J

F = 206.01 J / 3 m , 6.867 * 10 N

Eg. 3

h = 10 ^ -3 m

W = 7 kg * 9.81 m / s ^ 2 * 10 ^ -3 m

W = 6.867* 10 ^ -2 J ,

F = 6.867* 10 ^ -2 J / 10 ^ -3 m

F = 6.867 * 10 N

The method is simple and accounts for all mechanical deformation. The equation works perfectly for any deformation which does not exceed Hooke's Law.

© Sydney Matinga 2025